00:01
Okay, so we want to distinguish between the stereoisomers.
00:06
And a stereoisomer can be divided into a diastomer and an an ananomer.
00:11
And diastomers differ at at least one chiral center, and anantamers differ at all of them.
00:18
And a chiral center describes a carbon atom that's bound to four different groups.
00:24
So starting with diastomers, if we had these structures, so if we had a chlorine in the front, and as a result, we're going to have hydrogen in the back.
00:50
And we also have, well, actually, let's do this instead.
01:03
Have this, and then a bromine.
01:10
Okay, and then comparing that to this one.
01:35
So the best strategy here is just to first identify the configuration of the carol center.
01:45
So starting from left to right, the chlorine is one.
01:48
The hydrogen is four based the lowest atomic number.
01:51
And we're comparing ch2 on this carbon to chbr on that carbon and the burmine is a higher atomic number than the second hydrogen of ch2 so this side's going to be 3 i mean 2 and as a result the side is going to be 3 so going from 1 to 2 2 to 3 to 3 to 1 ignoring 4 the orientation of this carol center is going to be counterclockwise which is s and then the one in red bermine is 1 the c -cl or the chcl is more priority of the ch2.
02:29
Because chlorine is a higher atomic number than the hydrogen.
02:32
The hydrogen is four.
02:33
As a result, the sides three.
02:35
Going from 1 to 2, 2 to 3, and then eventually 3 to 1...