Name each ionic compound. a. SnCl4 b. PbI2 c. Fe2 O3 d. CuI2...

Name: Problem 17, Chapter 3: Principles of chemistry: A molecular approach
Uploaded: 2020-07-23T14:11:28-08:00
Duration: 11 min 47 s
Channel: Md Mohibullah
Description: Name each ionic compound. a. SnCl4 b. PbI2 c. Fe2 O3 d. CuI2

Key Concepts

Metal Cations and Oxidation States

Many metal ions can exhibit more than one possible oxidation state, particularly transition metals and some post-transition metals. When a metal has multiple oxidation states, a Roman numeral is used in parentheses immediately following the metal’s name to indicate its charge. This is essential for distinguishing compounds that contain the same metal but have different chemical properties.

Anion Naming Conventions

For binary ionic compounds, anions derived from single elements are named by taking the root of the element’s name and adding the suffix '-ide'. This convention is a standard practice in chemical nomenclature, helping to easily identify the non-metal component in the ionic compound.

Ionic Compounds

Ionic compounds are chemical compounds formed by the electrostatic attraction between positively charged ions (cations) and negatively charged ions (anions). They typically consist of a metal and a non-metal, although polyatomic ions may also be involved. The properties of ionic compounds include high melting and boiling points and electrical conductivity in molten or aqueous states.

Nomenclature of Ionic Compounds

The naming of ionic compounds follows systematic rules where the name of the cation is stated first, followed by the name of the anion. For binary ionic compounds, the non-metal anion’s name is modified to end in '-ide'. This structure ensures clarity and uniformity in chemical communication.

Transcript

00:01 So in this problem, we are asked to name each of the ionic compounds given.

00:04 So the first one we are given here is sncl4.

00:11 So to write down the name of an ionic compound, first you have to identify the cat ion and the anion present in that compound.

00:20 And then for naming, first we have to write down the cat ion name and then the anion name.

00:25 And if the cation can form more than one charge or if it has more than one oxidation state then we have to specify the oxidation state of that cation state present in that specific compound and then for writing down the name of the anion first we have to write down the base name of the anion and then we have to add one common end name which is ide at the end of each anion.

00:58 So let's first go step by step.

01:01 Our first step is to identify the cat -oan and anion.

01:04 And usually we know that in a binary compound, the first ion we have will be the cat -down usually and the following ion will be the anion.

01:15 So here our cat -ion here is s -n.

01:19 And our anion is cl so to name the compound first we have to identify the charge or the oxidation number of each of the atom ion so for chlorine as we know that chlorine is in group 7a that means chlorine will always need one electron to complete its octet and that's why chlorine will always possess a minus one charge and now we have to know what is the oxidation state or charge of t or s in this compound and for doing that what we can do we can identify the charge of the oxidation state of s n from the charge or oxidation state of chlorine since it's a fixed oxidation number for chlorine so here we see that chlorine's oxidation number is minus one and we have four chloride ions here that means the oxidation state for chlorine here is that that means we have in total minus 1 times 4 that means minus 4 charge for chlorine or chloride and as we know that in case of a compound the overall charge will be 0 or neutral that means our metallic ion or get ion must have an equal positive charge to neutralize this minus 4 charge that means sn should have a charge of plus 4 and now we have got the oxidation state or charge of sn, which is plus 4.

02:56 Now we have identified our cat -oan and anion with their charges.

03:01 Now we can write down the name.

03:02 For writing down, as we say that first we write down the name of the cat -ion.

03:08 So the cat -on here is tin.

03:11 So the name is s -n, which is stannum, which is the name of tin.

03:16 So we write down tin as the metal name.

03:22 And then as you said that if our metal atom ion can have or if can form multiple oxidation states, then we'll have to identify its oxidation state in that compound.

03:37 And this is a post -transition metal.

03:40 That means it can have more than one oxidation state.

03:42 That's we will specify this plus four oxidation state here in rome.

03:46 Numeral we'll write it as 4 t in 4 and then we'll write we'll write down the name of the anion and for naming down the anion first we'll write down the base name of the atom so the base name so the total or the entire name is chlorine and the base name will be clore clore and then we'll add this i'd at the end of anion so it will be chloride so the entire name is tin for chloride so this is the name for sncl4.

04:23 Now let's move to our next entry given, which is pbi2.

04:31 So from here, again, we first identify the cation and anion.

04:35 Here our cation is pb and anion is iodine.

04:39 So pb and i.

04:43 Again, pb is a post -transition metal.

04:46 That means it will have variable oxidation state.

04:49 And to identify or specify what excretion state pb has in this compound to know that first we have to identify the charge on iodine.

04:59 I already is also in group 7a and it has a fixed charge of minus 1.

05:04 And now we have two iodine present here.

05:07 That means the total charge on iodine here is minus 1 times 2.

05:14 That means minus 2.

05:16 Now to keep the compound neutral, we must have a plus 2 charge for the lead to neutralize this minus 2.