00:01
We're making us to name each of the following compounds.
00:04
And so as per usual with naming, i'm going to start numbering my carbons, starting with the carbon that is closest to the branching.
00:12
So in a, my first carbon would be here.
00:17
My second would be here, third here, and fourth here.
00:23
So because there are no double bonds, we know that this is in alkan.
00:27
It's a saturated hydrocarbon.
00:29
And the longest continuous chain of carbons has four, so my root is going to be butane.
00:37
I should also note that i do have a chlorine atom bonded to the first and the third carbons.
00:47
So the name for this will be 1, 3, die, because there's 2 chlorine atoms, di chloro, and our root is butane.
01:03
So my name for this structure will be 1 -3 dichlorobutane.
01:10
For b, we'll follow a similar process.
01:13
I'll start numbering my carbons.
01:16
My first is here because the closest branching is going to be to the three chlorine atoms here, two, three, four.
01:26
Just like with part a, my root for this is going to be a butane.
01:29
And i have three substituents, three chlorine atoms off of the first carbon.
01:38
So all three of them are off of the first.
01:43
It'll be tri -chloro because there's three chlorine atoms, and our root is butane...