00:01
Let's go over some binary compounds and determine what kind of bonds they form.
00:07
We know that the differences in electronegativities between the two elements of a binary compound will tell us whether the bond is pure covalent, polar covalent, or ionic.
00:23
The bond will be pure covalent if the differences in electronegativities are less than 0 .4.
00:32
The bond will be polar covalent if the differences in electron negativities are between 0 .4 and 1 .8.
00:49
And we know that if the differences in electron negatives are greater than 1 .8 between the two elements of a binary compound, the bond they share will most likely be ionic.
01:06
So let's do some examples.
01:09
First binary compound we'll explore is f .e .3 .3.
01:18
3p2.
01:23
Well, the iron species has an electronegativity of 2 .1, or excuse me, the phosphorus species has an electronegativity of 2 .1, and iron has an electrotativity of 1 .8, giving us a difference in electron negativity of 0 .3, and that will be less than 0 .4.
01:48
Therefore, it will be pure covalent.
01:50
The next binary molecule we'll look at is calcium bromide, c -a -b -r -2.
02:06
Bromene has an electronegativity of 2 .8, and calcium has an electronegativity of 1, giving us a difference in electronegativity of 1 .8.
02:24
That difference in electronegativity tells us that the bonds between calcium and bromide are ionic, and in fact the calcium will donate its electron density to bromine as opposed to sharing it equally or sharing it unequally in the cases of pure covalent and polar covalent bonds respectively...