00:04
Okay.
00:05
So we are going to look at naming our compounds here.
00:08
We have some cyclic.
00:09
We also have one.
00:11
Our first one is just a linear compound, right? or a straight, well, not a cyclic compound.
00:17
So we do have four carbons in that first chain.
00:21
We see a double bond.
00:22
Now, the double bond does get priority in numbering.
00:25
So we are going to number this one right to left.
00:29
So the double bond is on that first carbon, which means the chlorine is found on the third carbon.
00:35
So we have three chloro, one, butene, e &e for the double bond.
00:45
Then we get to a cyclic compound.
00:47
So we have a five ring compound here, a five carbon ring.
00:52
So we do have to look at that in terms of where the substituents are.
00:59
So it looks like our ethyl group is on the same carbon as the double bond.
01:05
So we can number that number one.
01:06
So we have a one ethyl, and then the methyl from there is on number three.
01:14
So if we count the first one as one and we count over two, we get to the methyl.
01:21
And then it's a cyclopentine.
01:29
And we don't have to number that double bond because we're assuming that we know that's where the methyl is.
01:35
Sorry, that's where the ethel is based on our number priority.
01:42
Right.
01:43
After that we have a cyclo another cyclopentine.
01:46
Our numbering is going to be a little bit different this time.
01:50
We are going to still number our double bond as number one, which puts the, let's see, that puts the chloro at number three.
02:03
So it'll be a three chloro, and the propyl group, or that three carbon chain, at number four, and that's a cyclopentine again.
02:22
Right, then we come to a hexane, a cyclohexane...