00:01
Okay, we're asked to give formula or draw the following structures.
00:03
First one is cis 2 -pentine.
00:06
So cis meaning that both the highest priority groups from the same side of the double bond, and pencine is 5 carbons, or pencine is 5 carbons.
00:16
I think it's easiest to draw the alken first, the 2 -carbon al -alkeen first, and then put the groups on the other side of the double bond.
00:27
So the al -keens on carbon 2, which means we're going to put a methyl down here, hydrogen here, methyl has more priority of the hydrogen because the carbon is a higher atomic number.
00:42
And as a result, we're going to put the rest of the chain down here because it's cis.
00:47
Three, we need two more carbons.
00:53
Look at that.
00:56
And if we want to give a formula, we have five carbons in total in pencene.
01:01
And looking at the hydrogens, we have three here, four, five, six, seven, and then three at the end.
01:11
So, i have ten.
01:15
Now the next one is one -six -dichloric.
01:18
Or 3 hex line.
01:22
Okay, so the ion ending positive of an al -kind, and it's on carbon of 3.
01:25
We're going to draw the structure first, like in a line.
01:32
Let's see it 3.
01:34
See al -kind.
01:36
And we have chlorines on carbon 1 and 6, just right here.
01:51
And for a formula, of 6 carbons, so it was c6.
01:57
We're going to have two hydrogens here.
02:00
2, 4, and then none.
02:04
There's no, there aren't any hydrogen, on these carbons...