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Hey guys, problem 9 .1 asks us to name various alkynes.
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I converted the compounds into line structures for clarity.
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When naming molecules is important to first identify the longest carbon chain, beginning with the carbon that is closest to a multiple bond.
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So we will begin by numbering this chain.
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We see that we have hexine and that there are two methyl groups on carbons 2 and 5.
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So this molecule will be named 2, 5, thymethyl, 3, hexine.
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Now let's look at part b.
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This is obviously the correct side to start with, so we'll number these carbons.
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And we see we have butine, and that there are two method groups on carbon 3.
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So this is going to be called 3, 3, 3, thymethyl one through time.
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Some textbooks will not include the one because if the carbon number is not specified on which a double bond begins, it is assumed to be the first carbon.
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Now on compound c, we will also begin numbering from the left because that is the side nearest to the first substituents and also it doesn't matter which side we number the chain because for the bond because it begins on carbon four on each side this is going to be this will be octane and again we have two methyl groups on carbon three so this is going to be three three thymethyl, four.
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Now let's look at the second three parts of this question.
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For part d, we will start naming the compound from the right side because the bond starts on carbon three.
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So this will be one, two, three, four, five, six, seven...