00:01
Okay, so in this problem, you have different alkenes that are depicted as line angle structures, and you want to go ahead and name each of these.
00:16
So when you're naming these structures, the first thing you want to do is identify the longest carbon chain.
00:24
So remember that this is a carbon, this is a carbon, three, four, five, six.
00:30
So basically each point on this line angle structure is representative of a carbon.
00:37
So if you look here, you have six carbons in your longest chain.
00:43
So if you have six carbons, if you start numbering from the left, you have one, two, three for your double bond.
00:49
If you start numbering from the right, you have one, two, three for your double bond.
00:53
And so because of that, you want to look for any constituents.
00:57
So let me write, the carbon double bond is on carbon three.
01:03
So you have this methyl group here.
01:08
So you would start numbering from the left to give your methyl group a lower number.
01:12
So we'd call this one, two, three, four, five, six.
01:17
So methyl is on carbon three.
01:21
So if you name this structure, we'll actually ignore e -and -zine nomenclature for a moment.
01:27
But we call this three -methyl, three hexene.
01:34
So when we're looking about enz nomenclature, we want to identify our highest priority on each carbon.
01:43
So on carbon 3, our ethyl has a higher priority that our methyl.
01:47
I'm just going to say h for higher priority.
01:51
On carbon 4, we have a hydrogen here.
01:54
So our ethel has a higher priority than our hydrogen.
01:57
So we call this h here for higher.
02:02
So because our higher priority groups are on opposite sides, we call this e.
02:14
So our second structure here, again, we want to identify our longest carbon chain.
02:20
So we have one, two, three, four, five, six, seven, eight, nine carbons.
02:27
So, and i think i actually, okay, so we identified our longest carbon chain.
02:39
I thought i was looking at the long problem.
02:44
But now we want to give our double bond the lowest numbering possible.
02:49
So if we start numbering from the left, we have one.
02:51
Two, three, four, five.
02:52
If we start numbering from the right, we have one, two, three, four.
02:56
So one, two, three, four, five, six, seven, eight, nine.
03:03
So our double bond is on carbon four.
03:06
And we also have a methyl group on carbon eight.
03:10
So again, we want to ignore e and z notation.
03:15
So we're going to say that this is eight methyl for non -een.
03:25
And if we're assigning e and z notation, we can draw in our hydrogens here.
03:33
And so on carbon 4, our higher priority group is our propal group.
03:39
I'll actually draw it out as high instead of h, so it's not confusing with hydrogen...