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Name the following coordination compounds (Section 28.3):(a) $\left[\mathrm{NiI}\left(\mathrm{NH}_{3}\right)_{5}\right] \mathrm{NO}_{3} ;$ (b) $\mathrm{K}\left[\mathrm{Co}(\mathrm{ox})_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right] ;$ (c) $\left[\mathrm{Fe}(\mathrm{dien})_{2}\right] \mathrm{SO}_{4} ;$(d) $\mathrm{Na}\left[\mathrm{AuBr}_{2} \mathrm{Cl}_{2}\right]$.
Chemistry 102
Chapter 28
d-Block chemistry
Transition Metals
Carleton College
University of Central Florida
Rice University
Drexel University
Lectures
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Name the following coordin…
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02:31
Hello everyone. Let us see the following question. Name the following coordination compounds. So we have to name with the U. P. A. C. Norman please of the following coordination company. So let us name the first one. There is a nickel in the central metal so there is five ammonia NH three total five times. And then we have to close the complex and then put in no. Three. So we know the oxidation number here. The oxidation number of nitrate is -1 each. A mine has zero oxidation state. So that means total charge of the complexes plus one. So that means the oxidation number of Nicole has to be plus one here. So it has to be nickel and there is one iodine missing. So let me draw the iodine. So it has also iodine. That means iodine once again contains minus one oxidation state. That means this is having plus two oxidation stick. So the name of the compound will name it. So it is named as and first always legal followed by the central metal. First we have to name the Carlton. Always Carlton, followed by. So Carlton is a complex. So in the complex we are done in the league. And first so we have spent our might bank to online then alphabetically next year. Okay then it is nickel, nickel is a positive metals species. So the complex has two and then 93. Let us draw the next one in the option B. We are having following structure. There is potassium which is a Cartier on an ion is a complex with the co bart Exhilarate or two times and then water two times. So we know that each water has zero oxidation state. Oscillator has minus one oxidation state. So it is minus two. Then that means cobalt has plus two oxidation state. If K is plus one overall charge of the complex is minus one. If it has to retain minus one oxalate or two times minus two into two. So it is minus four. That means this has to be plus three. Each oscillator has minus to charge total two times four minus four. If it is still minus then it has to be cobalt plus three. So the name of the charge Carlton is potassium partition first. Now the Ligon in the an eye. On first day Ako water is a co next to dioxins. Alito di auxerre, alito COBOL state. Why? Because the ann ions central mentality. So with the oxidation number three. So let us see the sea in C. I am having I. N. F. Okay then it is written by in It is two times close the bracket. Selfish. So the oxidation number will be here if it is -2. If it is plus two, this has no charge. So iron has to have plus two oxidation state. So the name here goes like this. So already dying. What is dying's full name? It is one comma 4. Okay, try as a gypsy. It is hard to try as a hip. Thanks. This is dying already. It is two times. So I'm writing a test this it is written as this this then iron three. Okay so it's two Celtic. Okay. Next option B. In option D. We have we have the right sodium open the complex gold VR two C. A. So since the oxidation state is plus one, this has to be minus one, this is minus two and minus two minus four. So gold has to be plus three. So let us write the name. So it is Cartier on first. That is anyway sodium. Okay so alphabetically brewing first. So die bro. More di chlor. Oh all right. Why the special name? Because an ionic complex? Yes. Thank you.
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