00:01
So for this question, we want to name a number of compounds, and we're going to do so in a number of ways for questions like this first one.
00:11
We're going to look at what makes up the compound, and here we see this is a nitrate, and we know this is barium, so we know the name to be barium nitrate.
00:35
So we can look at b.
00:39
And if we look at the oxidation state, so we're looking here at the oxidation state of nitrogen.
00:46
If we were to calculate this out to find the oxidation state, we would find that it was positive three.
00:51
And since it is positive three, that means our ending is going to be oss, which is based on how many oxidation states of nitrogen there are.
01:02
So we know this to be nitrous acid because of that acidic.
01:11
Hydrogen.
01:13
And then for cro2, which is chromium and two oxygen, we know the oxidation state of oxygen is negative 2, and then we can calculate to find the oxidation state of chromium, and we find it to be a positive 4.
01:31
So we can find the name of c to be chromium.
01:42
Since this is a metal, we'll do 4 oxide.
01:53
And we always are going to use the roman numerals, as i did for c.
01:57
And then we can move on to look at d.
02:00
And like we did in a, look at what is made up of.
02:04
And we find this to be iodate.
02:10
So that means our name is potassium iodate.
02:24
Then we can go down and look at e first.
02:33
So for e we see a lithium, carbon, and a nitrogen.
02:38
And we know this to be cyanide...