For (a) $\mathrm{BaBr}_2 \cdot 2 \mathrm{H}_2 \mathrm{O}$, the cation is $\mathrm{Ba}^{2+}$ (barium) and the anion is $\mathrm{Br}^-$ (bromide). For (b) $\mathrm{AlCl}_3 \cdot 6 \mathrm{H}_2 \mathrm{O}$, the cation is $\mathrm{Al}^{3+}$ (aluminum) and the anion is
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