Question
Natural gas as a mixture of $75 \%$ methane and $25 \%$ ethane by mass is flowing to a compressor at $17^{\circ} \mathrm{C}, 100 \mathrm{kPa}$. The reversible adiabatic compressor brings the flow to $350 \mathrm{kPa}$. Find the exit temperature and the needed work per kilogram of flow
Step 1
For methane, $R = 0.5183 \, \text{kJ/kg.K}$ and for ethane, $R = 0.2765 \, \text{kJ/kg.K}$. Thus, we have \[R_{mixture} = 0.75 \times 0.5183 + 0.25 \times 0.2765 = 0.45785 \, \text{kJ/kg.K}.\] Show more…
Show all steps
Your feedback will help us improve your experience
Varsha Aggarwal and 75 other Physics 103 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Natural gas as a mixture of $75 \%$ methane and $25 \%$ ethane by mass is flowing to a compressor at $17^{\circ} \mathrm{C}$ and $100 \mathrm{kPa}$. The reversible adiabatic compressor brings the flow to $250 \mathrm{kPa}$. Find the exit temperature and the needed work per $\mathrm{kg}$ flow.
A gaseous mixture consists of 75 percent methane and 25 percent ethane by mass. 2 million cubic feet of this mixture is trapped in a geological formation as natural gas at $300^{\circ} \mathrm{F}$ and 1300 psia. This natural gas is pumped $6000 \mathrm{ft}$ to the surface. At the surface, the gas pressure is 20 psia and its temperature is $200^{\circ} \mathrm{F}$. Using Kay's rule and the enthalpy-departure charts, calculate the work required to pump this gas.
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD