00:01
Given the balanced equation for the combustion of butane, let's answer the following questions.
00:06
For a, how many grams of butane can be burned by 1 .42 moles of oxygen? so we're starting with 1 .42 moles of oxygen.
00:18
We have 13 moles of oxygen.
00:23
2 moles of butane, c4h10.
00:28
1 mole of butane has a molar mass of 58 .0 grams.
00:46
This would be equal to 12 .7 grams of butane.
01:04
For b, if 9 .43 grams of oxygen is used in burning butane, how many moles of water results, starting from 9 .43 grams of oxygen.
01:19
Convert to moles, molar mass of oxygen is 32 grams.
01:24
We have 13 moles of oxygen to 10 moles of water.
01:36
Water, molar mass of 18 grams...