00:01
At a height of 12 meters, a ball has velocity 5 .60x plus 4 .10y meters per second.
00:08
To what maximum height will it rise? what horizontal distance will it travel before it hits the ground? and what is the velocity when it hits the ground? so this is a question that asks us to use projectile motion equations.
00:19
First, we're going to identify the given given given y not equals 12 .5, x not equals 0, x .0 equals 5 .6 meters per second, and v .y not equals 4 .10 meters per second.
00:32
First, we want to see what the max height will rise to.
00:36
Instead, though, what we're going to do is use h equals y -0 plus v -y -nott squared over 2g, the equation for maximum height, plugging in our y -0 v.
00:44
Y -y -not and g equals 9 .481 gives 13 .4 meters.
00:48
Next, the time that it hits the ground is found using the equation for y, plugging in our y -not of 12 .5, and our y equals 0 because we're waiting until it hits the ground...