00:01
Okay, so in this problem, we have to calculate the angular speed of the electron for the ground state, which is when the quantum number is one, and for the first excited state, that is when the quantum number is 2.
00:23
And to calculate this, let's remember that the angular speed is just the speed, the radio speed, divided by the radius of the orbit.
00:39
Therefore, we need to find a way to describe the speed and the radius for this quantum numbers.
00:48
And first of all, we must remember that the radio speed, rn is described as 5 .29 times 10 to the minus 11 that multiplies n square divided by z.
01:12
So now how are we going to find to describe the speed? well remember of the angular momentum.
01:21
The angular momentum is just mvn, rn equals n h divided by 2 pi.
01:35
So we can say that the speed, the radio speed, is just an h divided by 2 pi m rn.
01:54
So using these two equations here, the blue one and the green one, we can calculate the angular speed for the electron.
02:06
So let's see.
02:10
The angular speed is going to be nh divided by 2 pi par and square.
02:26
They multiplies the mass of the particle.
02:32
And if we look to the problem, we want this answer in revolutions per second...