Question
Net resistance between $\mathrm{A}$ and $\mathrm{B}$ in the given network is....(A) $5(\mathrm{R} / 7)$(B) $7(\mathrm{R} / 6)$(C) $(4 \mathrm{R} / 5)$(D) $(6 \mathrm{R} / 7)$
Step 1
We find that two resistances of 2R are connected in parallel and are further connected with a resistance R. This pattern repeats itself in the circuit. Show more…
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Net resistance between $\mathrm{A}$ and $\mathrm{B}$ in the given network is $\ldots$ (A) $(5 \mathrm{r} / 7)$ (B) $(7 r / 6)$ (C) $(4 r / 5)$ (D) $(6 \mathrm{r} / 7)$
Net resistance between $\mathrm{A}$ and $\mathrm{B}$ in the given network is: (A) $(5 \mathrm{R} / 7)$ (B) $(7 R / 6)$ (C) $(4 \mathrm{R} / 5)$ (D) $(5 \mathrm{R} / 4)$
Net resistance between $\mathrm{A}$ and $\mathrm{B}$ in the given network is: (A) $5(\mathrm{R} / 7)$ (B) $7(\mathrm{R} / 6)$ (C) $3(\mathrm{R} / 2)$ (D) $5(\mathrm{R} / 4)$
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