00:01
In this question, we need to calculate the value of i1, i2 and i3.
00:06
Here i use nodal analysis method for solving this problem.
00:12
Now let assume that this is the node number 2 and this is the node number 1.
00:21
And node 1 voltage is v1 and node 2 voltage is v2.
00:27
I take node 2 as reference node so the voltage.
00:31
Of node v2 is equal to 0 so i ground node now i applied nodal analysis at node 1 so when i apply nodal analysis at node 1 i obtained this equation v1 minus a divided by 1 v1 minus a divide by 1 plus v1 minus v2 divide by 2 v1 minus v2 divide by 2 v1 minus v2 divided by 2 plus v1 minus b divided by 4 is equal to 0 here because node 2 voltage is equal to 0 so voltage at this terminal is equal to b and voltage at this terminal is equal to a now i simplify this equation.
01:40
So this equation will become v1, 1 plus 1 divided by 2 plus 1 divide by 4 is equal to a plus b divided by 4.
01:57
Now from here this will become 4, 4 plus 2 plus 1 plus 1 is equal to 4.
02:12
4 a plus b divided by 4 4 to 4 cancel out so from here i obtain v1 is equal to 4a plus b divided by 4 plus 2 plus 1 is equal to 7 now for case number first a is equal to 5 volt and b is equal to 8 volt so so i put the value of a and b in this equation...