00:01
We calculate several thermodynamic properties of the synthesis of nickel tetrocarbonil.
00:07
So the first thing we're going to do is calculate our enthalpy of reaction.
00:13
So to do this, we are going to subtract our reactants from our products using our standard enthalpyes of formation.
00:20
So starting with our products for our nickel tetracharboneal, we are given in the problem a delta h of formation of negative 633 .3 .3.
00:31
0 .0 kilojoules per mole.
00:35
For our reactants here we have that our nickel solid is going to be 0 kilojoules per mole because of solid metal.
00:42
And we're going to add that to 4 times our carbon monoxide, which is going to be negative 100 .5 kilojoules per mole.
00:53
This gives us a delta h standard value of negative 191 kilojoules per mole.
01:03
So we're going to calculate our delta s value in a very similar way.
01:07
We're going to use our standard delta s for each of these molecules, products minus reactants.
01:12
So we're given the problem that our standard delta s for nickel tetracharboneal is 313 .4 joules per mil kelvin.
01:24
Subtract that from our reactants here, where we have for nickel 29 .9 jules per mole kelvin plus our four times our carbon monoxide, which is going to be 197 .6 joules per mole kelvin.
01:42
This gives us a delta s standard value of negative 503, excuse me, 506 .9 joules per mole kelvin, or negative 0 .5069 kilojoules per mole.
02:02
So now that we have both of these values, we can go ahead and calculate our delta g.
02:07
We're going to use the equation here that our delta g standard is equal to our delta h standard minus t.
02:13
D -delta -s standard.
02:16
So we can go out and plug in some numbers here.
02:18
We know that negative 191 kilojoules per mole.
02:24
We're running at a temperature of 298 kelvin, so we can do that for our standard temperature, and then our entropy is going to be 0 .5069 kilojoules per mole kelvin.
02:40
This is going to give us a delta g standard value of negative 39 .9 kilojoules per mole.
02:56
Okay, so now that we have this value, we can do a couple different things.
03:01
First, we're going to calculate the temperature at which this reaction becomes non -spontaneous...