00:01
This question asks you to convert grams of a react into grams of another react into product.
00:07
To do this, we need a balanced chemical reaction that's provided in the problem.
00:11
First, you're asked to calculate how many grams of water needed to react with 28 grams of nitrogen dioxide.
00:18
So we'll start with the 28 grams nitrogen dioxide, divide by the molar mass nitrogen dioxide, to get moles nitrogen dioxide.
00:25
Then, using the stoichiometry of the balanced chemical reaction, convert the moles nitrogen dioxide three into moles of water, one.
00:34
When we have moles of water, we'll multiply by the molar mass of water to get grams water.
00:39
3 .65 grams water can be produced from 28 .0 grams nitrogen dioxide, or, sorry, 3 .6 grams water are needed to react with 28 .0 grams nitrogen dioxide...