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Problem 8

Nitrogen monoxide and oxygen react to form nitrog…


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Problem 7

Nitrogen $\left(\mathrm{N}_{2}\right)$ and hydrogen $\left(\mathrm{H}_{2}\right)$ react to form ammonia $\left(\mathrm{NH}_{3}\right) .$ Consider the mixture of $\mathrm{N}_{2}$ and $\mathrm{H}_{2}$ shown in the accompanying diagram. The blue spheres represent $\mathrm{N},$ and the white ones represent H. (a) Write the balanced chemical equation for the reaction. (b) What is the limiting reactant? (c) How many molecules of ammonia can be made, assuming the reaction goes to completion, based on the diagram? (d) Are any reactant molecules left over, based on the diagram? If so, how many of which type are left over? [ Section 3.7]


a) $\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightarrow 2 \mathrm{NH}_{3}$
b) The limiting reactant is hydrogen
c) 6 molecules of ammonia
d) 1 unreacted



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Video Transcript

for option A. We know that nitrogen and hydrogen reacts to form ammonia, which is an ex tree. The balance chemical equation would be shown us and do less. Three. H two gives us to move off image three. According to this equation, one more off nitrogen reacts with three moles off edge to to provide us with two moles off ammonia that is in the street for option B Out off. The to the reaction that is completely consumed in the reaction is the limiting the agent. From the above equation. It is clear that one molecule off night, Wooten reacts with three molecules off hydrogen to form two molecules off ammonia. No, consider a situation. We have spears, the black on dhe, the white spirit. So here we have a total off full spit. Consider these forced beers as full molecule. The black one represents night toward you by the white one represents hydrogen on DDE, so we have total off four molecules off nitrogen on dhe nine molecules, both hydrogen for auction. See, we have a table representation. According to the table, hydrogen is completely consumed, which act as a limiting the agent or option C. We have the balance chemical equation. It is clear that one more nickel off nitrogen reacts with three molecules of hydrogen to give us to ammonia. No. In the given diagram, the blue spare represents and toe while whites spare represent its toe. We have four molecules off into on nine molecules off its toe from the table in part B. It is clear that six molecules off ammonia can be made, assuming the reaction goes to completion. No, we have last option. Dean again from the table in part B, one molecule off nitrogen and two is left unknown. Reacted? Yeah, you know.

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