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For this problem on the topic of causser's law, we have shown a non -conducting spherical shell, which has an inner radius of 2 .4 centimeters, the inner and outer radius of 2 .4 centimeters, the inner and outer radia are represented by a and b respectively, and it has a positive volume charge density row, which is equal to capital a over r, where capital a is a constant, and r is the distance from the center of the shell.
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Now, in addition, we have a small ball of charge of 45 femto -culeums located at the center.
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Want to know the value that big a should have if the electric field in the shell is to be uniform.
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Now, to find an expression for the electric field inside the shell in terms of a and the distance from the center of the shell, we will choose a so that the field does not depend on the distance.
00:46
We use a gaussian surface in the form of a sphere with radius rg, concentric with the spherical shell and within it, so that a is less than rg, which is less than b.
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Gauss's law can be used to find the magnitude of the electric field at a distance rg from the shell center.
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The charge that is both in the shell and within the gaussian sphere is given by the integral, and we'll call it qs is equal to the integral of row dv over the portion of the shell within the gaussian surface...