Question
Normal atmospheric pressure is $1.013 \times 10^{5} \mathrm{Pa}$. The approach of a storm causes the height of a mercury barometer to drop by $20.0 \mathrm{mm}$ from the normal height. What is the atmospheric pressure? (The density of mercury is $\left.13.59 \mathrm{g} / \mathrm{cm}^{3} .\right)$
Step 1
Step 1: We know that the pressure is given by the formula $P = \rho g h$, where $\rho$ is the density, $g$ is the acceleration due to gravity, and $h$ is the height. Show more…
Show all steps
Your feedback will help us improve your experience
Ma Ednelyn Lim and 53 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Normal atmospheric pressure is $1.013 \times 10^{5}$ Pa. The approach of a storm causes the height of a mercury barometer to drop by 20.0 $\mathrm{mm}$ from the normal height. What is the atmospheric pressure? (The density of mercury is $13.59 \mathrm{g} / \mathrm{cm}^{3} . )$
Normal atmospheric pressure is $1.013 \times 10^{5}$ Pa. The approach of a storm causes the height of a mercury barometer to drop by 20.0 $\mathrm{mm}$ from the normal height. What is the atmospheric pressure?
When a barometer reads an atmospheric pressure as $734 \mathrm{~mm}$ of $\mathrm{Hg}$, what is the pressure in $\mathrm{N} / \mathrm{m}^{2} ?$ (The density of mercury is $13,600 \mathrm{~kg} / \mathrm{m}^{3} .$ )
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD