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Problem 23

What is osmosis? What is osmotic pressure?

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Problem 23

What is osmosis? What is osmotic pressure?
Problem 23

Prove Property 1 of Theorem 11
Problem 23

For the same signal emitted by a radio antenna,
Observer A measures its intensity to be 16 times the
intensity measured by Observer B. The distance of
Observer A from the radio antenna is what fraction
of the distance of Observer B from the radio
antenna?
\begin{equation}\begin{array}{l}{\text { A) } \frac{1}{4}} \\ {\text { B) } \frac{1}{16}} \\ {\text { C) } \frac{1}{64}} \\ {\text { D) } \frac{1}{256}}\end{array}\end{equation}
Problem 23

Which statement best captures Ken Dial's central
assumption in setting up his research?
\begin{equation}
\begin{array}{l}{\text { A) The acquisition of flight in young birds sheds }} \\ {\text { light on the acquisition of flight in their }} \\ {\text { evolutionary ancestors. }} \\ {\text { B) The tendency of certain young birds to jump }} \\ {\text { erratically is a somewhat recent evolved }} \\ {\text { behavior. }}\\{\text { C) Young birds in a controlled research setting are }} \\ {\text { less likely than birds in the wild to require }} \\ {\text { perches when at rest. }} \\ {\text { D) Ground-dwelling and tree-climbing predecessors }} \\ {\text { to birds evolved in parallel. }}\end{array}
\end{equation}
Problem 23

A) NO CHANGE
B) living along the West Coast of North America,
they help
C) that live along the West Coast of North America
and help to
D) that live along the West Coast of North America,
where they help
Lily A.
Johns Hopkins University
Problem 1 Problem 1 Problem 1 Problem 1 Problem 1 Problem 1 Problem 1 Problem 1 Problem 2 Problem 2 Problem 2 Problem 2 Problem 2 Problem 2 Problem 2 Problem 2 Problem 3 Problem 3 Problem 3 Problem 3 Problem 3 Problem 3 Problem 3 Problem 3 Problem 4 Problem 4 Problem 4 Problem 4 Problem 4 Problem 4 Problem 4 Problem 4 Problem 5 Problem 5 Problem 5 Problem 5 Problem 5 Problem 5 Problem 5 Problem 5 Problem 6 Problem 6 Problem 6 Problem 6 Problem 6 Problem 6 Problem 6 Problem 6 Problem 7 Problem 7 Problem 7 Problem 7 Problem 7 Problem 7 Problem 7 Problem 7 Problem 8 Problem 8 Problem 8 Problem 8 Problem 8 Problem 8 Problem 8 Problem 8 Problem 9 Problem 9 Problem 9 Problem 9 Problem 9 Problem 9 Problem 9 Problem 9 Problem 10 Problem 10 Problem 10 Problem 10 Problem 10 Problem 10 Problem 10 Problem 10 Problem 11 Problem 11 Problem 11 Problem 11 Problem 11 Problem 11 Problem 11 Problem 11 Problem 12 Problem 12 Problem 12 Problem 12 Problem 12 Problem 12 Problem 12 Problem 12 Problem 13 Problem 13 Problem 13 Problem 13 Problem 13 Problem 13 Problem 13 Problem 13 Problem 14 Problem 14 Problem 14 Problem 14 Problem 14 Problem 14 Problem 14 Problem 14 Problem 15 Problem 15 Problem 15 Problem 15 Problem 15 Problem 15 Problem 15 Problem 15 Problem 16 Problem 16 Problem 16 Problem 16 Problem 16 Problem 16 Problem 16 Problem 17 Problem 17 Problem 17 Problem 17 Problem 17 Problem 17 Problem 17 Problem 17 Problem 18 Problem 18 Problem 18 Problem 18 Problem 18 Problem 18 Problem 18 Problem 18 Problem 19 Problem 19 Problem 19 Problem 19 Problem 19 Problem 19 Problem 19 Problem 19 Problem 20 Problem 20 Problem 20 Problem 20 Problem 20 Problem 20 Problem 20 Problem 20 Problem 21 Problem 21 Problem 21 Problem 21 Problem 21 Problem 21 Problem 21 Problem 21 Problem 22 Problem 22 Problem 22 Problem 22 Problem 22 Problem 22 Problem 22 Problem 22 Problem 23 Problem 23 Problem 23 Problem 23 Problem 23 Problem 23 Problem 23 Problem 23 Problem 24 Problem 24 Problem 24 Problem 24 Problem 24 Problem 24 Problem 24 Problem 24 Problem 25 Problem 25 Problem 25 Problem 25 Problem 25 Problem 25 Problem 25 Problem 25 Problem 26 Problem 26 Problem 26 Problem 26 Problem 26 Problem 26 Problem 26 Problem 26 Problem 27 Problem 27 Problem 27 Problem 27 Problem 27 Problem 27 Problem 27 Problem 27 Problem 28 Problem 28 Problem 28 Problem 28 Problem 28 Problem 28 Problem 28 Problem 28 Problem 29 Problem 29 Problem 29 Problem 29 Problem 29 Problem 29 Problem 29 Problem 29 Problem 30 Problem 30 Problem 30 Problem 30 Problem 30 Problem 30 Problem 30 Problem 30 Problem 31 Problem 31 Problem 31 Problem 31 Problem 31 Problem 31 Problem 31 Problem 31 Problem 32 Problem 32 Problem 32 Problem 32 Problem 32 Problem 32 Problem 32 Problem 32 Problem 33 Problem 33 Problem 33 Problem 33 Problem 33 Problem 33 Problem 33 Problem 33 Problem 34 Problem 34 Problem 34 Problem 34 Problem 34 Problem 34 Problem 34 Problem 34 Problem 35 Problem 35 Problem 35 Problem 35 Problem 35 Problem 35 Problem 35 Problem 35 Problem 36 Problem 36 Problem 36 Problem 36 Problem 36 Problem 36 Problem 36 Problem 36 Problem 37 Problem 37 Problem 37 Problem 37 Problem 37 Problem 37 Problem 37 Problem 37 Problem 37 Problem 38 Problem 38 Problem 38 Problem 38 Problem 38 Problem 38 Problem 38 Problem 38 Problem 38

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Problem 22

Number of States with 10 or More
Electoral Votes in 2008
In $2008,$ there were 21 states with 10 or more
electoral votes, as shown in the table above. Based on
the table, what was the median number of electoral
votes for the 21 states?
$$\begin{array}{l}{\text { A) } 13} \\ {\text { B) } 15} \\ {\text { C) } 17} \\ {\text { D) } 20}\end{array}$$

Answer
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SAT
SAT Practice Test # 6

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Video Transcript

So, first of all, if we're looking for the medium was going to find that really quick. Well, median is just the middle number when the data points are arranged from lowest heist. So then we'LL think about how we read this frequency distribution table. So frequency distribution is a little bit different and that this tells us how many of this we have. So we have four tenants that's excellent. Turned ten times ten four Elevens, betweens that eleven one on one Pleven one twelve. So one twelve one thirteen So on so forth. That's how we read that frequency distribution table. And then it says that we want to find the median of that. So then if we want to find the median and we know that, then we have to first find out how many states there were, which it says that they're twenty one states. Twenty one is the total number of data points. So then we have to find a middle of twenty one. So then we just divide that by two, and that gives us ten point five in which frees when we have an odd number of data points. We just have to round up. So this one is going to be the eleventh state of point is going to be immediate. It was, for example, if we had three data points eight, nine and eleven, you just take that three. Divide that by two because one point five, we round up to two. So then your second data point is going to be the meat in which works. So then, that we know that if you want to pick the level data point, the first through the foreign are for ten, just through the eighth are eleven. Ninth is twelve. Tenth is thirteen eleven through thirteenth is fifteen, so we know that fifteen is going to be our medium.

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