00:01
For this problem, we are asked to find the mclaurin series for the function f of x equals lon of 1 plus x using the definition of a mclaren series.
00:09
We'll start by evaluating our function at 0.
00:12
We have f of 0's lawn of 1, which is just 0.
00:16
Then we want to find f prime of x.
00:19
Now, derivative of lon of x would be 1 over x, so this is going to go to 1 over 1 plus x.
00:25
And we'd have then that f prime of 0 is going to equal 1.
00:30
Prime of 0, or f double prime of x, i should say first, it's going to be given by negative 1 over 1 plus x squared.
00:41
So f double prime of 0 is going to be given by negative 1.
00:45
F triple prime of x is going to be given by negative 2 times negative 1, or i'll say that it's given by negative 1 to the power of 2 times 2 times 1 over 1 plus x to the power of 3.
01:02
So f triple prime of 0 is going to be just 2.
01:08
And i'll go up to the fourth derivative here, in which case we'd have that this is given by negative 1 to the power of 3 times 3 times 2 times 1 divided by 1 plus x cubed, which then means that the fourth derivative at 0 is going to be negative 3 times 2 times 1...