00:01
So we know that the p had, or the random sample that they took, had 180 people saying that the resume inflation was unethical out of 250 people.
00:10
And this decimal is 0 .72.
00:13
And they got a confidence interval that went from 0 .68 to 0 .76.
00:20
And we want to know what is that confidence level.
00:26
And so we know that the width of this interval is equal to 0 .6.
00:33
Subtracting these 2, 0 .68 minus this is going to give us a 0 .08.
00:40
And we know that width is 2 times the margin of error, and the margin of error is some z value times the square root of .72 times 1 minus .72, which is .28, divided by the 250 sample size.
00:58
So if i solve for z, that's going to end up being that 0 .08 divided by 2 and then divided by, divided by that big square root, the square root of 0 .72 times 0 .28 divided by 250.
01:21
And when i do that calculation, i get the z values 1 .40 and it come about to be like 86...