00:01
So for this problem, we're going to be exploring scatter plots, equations, deriving the equations to graph lines, and then incorporating some graphing utilities to represent those lines of best fit.
00:13
So we have this given data set.
00:16
I've already created the scatter plot for it.
00:19
So notice that on the x -axis, the intervals are 1 and then on the y -axis, the intervals are 2, just to make sure that i'm able to include the largest numbers in the data set.
00:29
And so we have this scatter plot.
00:31
We can definitely see that this is, it's close to linear, but not exactly linear.
00:35
We see that some of the points are kind of also not perfectly in a straight line.
00:39
So what we're going to do is when we do have data that doesn't lay in a perfectly straight line, we can still find a close to linear relationship based off of two data points that we feel like is a good representation of that overall picture.
00:54
And so for that purpose, i'm going to select the two order pairs four, six.
00:59
And 610.
01:01
And what i'm going to do is i am going to try to determine the equation for this set of data using a linear representation based off of these two points.
01:13
And so if i wanted to write an equation for this, i'm going to start off by doing the equation in point slope form, since i can easily find both of those pieces of information.
01:25
So the equation and point slope form is going to be in the format of y minus y1 equals m multiplied by x minus x1.
01:37
And so the slope is rise over run or the change in y over the change in x.
01:42
So for these two points, the change in y is four.
01:45
The change in x is two and then four divided by two equals two.
01:49
So i know the slope is going to be two.
01:50
And then i can use either one of these points to fill in from my x1 y1.
01:55
And so since this just represents the coordinates of one of the points, i'll just use the order here for.
02:00
And six.
02:00
And so from that order of pair, the y value is going to be six, and the x value is going to be four.
02:08
And then if i wanted to convert the same equation into slope intercept form, since later on we're going to be x to represent that in slope intercept form, then i will convert that.
02:24
And i just want to scoge this over a little bit.
02:25
So to convert that into slope intercept form, where's that typing tool at, there we go.
02:33
Okay.
02:33
So i want to get the y by itself to get an insult intercept form.
02:37
So y is going to see on the left side of the equal sign that six, we're going to move it over to the other side.
02:43
So we'll still have that two.
02:45
We'll have the x minus four.
02:47
And then we want to move over the six.
02:49
So it's going to become plus six.
02:50
And then next after that, we still have y by itself, which is what we want.
02:55
And then we're going to distribute the two to everything inside of the parentheses.
02:59
So that's going to give us 2x...