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Off to Europe! You plan to take your hair blower to Europe, where the electrical outlets put out 240 $\mathrm{V}$ instead of the 120 $\mathrm{V}$ seen in the United States. The blower puts out 1600 $\mathrm{W}$ at 120 $\mathrm{V}$ . (a) What could you do to operate your blower via the 240 $\mathrm{V}$ line in Europe? (b) What current will your blower draw from a European outlet? (c) What resistance will your blower appear to have when operated at 240 $\mathrm{V} ?$

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a. 2.5 $\mathrm{A}$b. 3235.3$\Omega$c

Physics 102 Electricity and Magnetism

Chapter 21

Electromagnetic Induction

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Magnetic Field and Magnetic Forces

Sources of Magnetic field

Inductance

Alternating Current

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Washington

Hope College

Lectures

03:27

Electromagnetic induction is the production of an electromotive force (emf) across a conductor due to its dynamic interaction with a magnetic field. Michael Faraday is generally credited with the discovery of electromagnetic induction in 1831.

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In physics, a magnetic field is a vector field that describes the magnetic influence of electric currents and magnetic materials. The magnetic field at any given point is specified by both a direction and a magnitude (or strength); as such it is a vector field. The term is used for two distinct but closely related fields denoted by the symbols B and H, where H is measured in units of amperes per meter (usually in the cgs system of units) and B is measured in teslas (SI units).

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that this problem? We have 100 and 20 volts hair blower, and at this voltage it puts out 1600 watts. But we want to operate it with the 240 volt out. The first question is, how do we operate this at 240 boats and we see that this is a transformer problem. So the primary is gonna be 240 volt outlet on our secondary is ah 120 volt hair blower. We know that the ratio of the turns between secondary in the primary is equivalent to the voltage ray shell secondary to the primary here that it's 1 20 over to 40 wanna have. So this tells us to operate it at 120 volts to step down the voltage from 2 40 to 1 20 We need the secondary to have half the number of terms that are in the primary. The second part. We want to know how much current is drawn from the outlet, and we can do this with conservation of energy. Whatever power is delivered to the primary is then delivered to the secondary is taken out. So what's drawn from the output is delivered to the secondary, meaning our power being equal to the current times of voltage. What's delivered to the primary was in transmitted to the secondary, and we're told that at 120 votes, the blower puts out 1600 watts. So now we can solve for what? Our colonels, the 1 1600 watts. And this is 240 for the primary. We plugged that in and we get six point 67 amps. The last question. We want to know what resistance the blower appears tohave in this set up. So the resistance that the blower appears tohave will be whatever effective resistance is on the primary side, we can think about. We have some voltage up here. We have some effective resistance, this being our primary side of things. Then we have our little hair butter. But that is a church that's grounded. So we want to know what this effective resistance is. I'll show you two different ways to do that one the most obvious or the the quickest way to do that is to say that are effective is just gonna be whatever are primary voltages divided by the current we just found what that current is. So this is gonna be 240 votes divided by 6.67 lamps. And if we plug that in, we get 36 homes. The other way to do this is to utilize one of the equations in her book, which tells us that the effective resistance is gonna be given by the resistance on the secondary side, divided by our ratio of turns square. Now, we don't know this resistance on the secondary signs we'll have to rewrite. That would be too over. I too two over and one squared. We don't know the I too, but we know the power. So this will be V two squared over p A. That's use utilizing this equation and such over Gracia that squared. And now we have all of these pieces. So we know that there secondary voltage is 120 squared power delivered is 1600 and then this ratio is 1/2. This is 1/2 square and then this If you plug everything in, also gets 37 36 pups and you'll see that the first route was obviously a lot quicker. But just a nice consistency that you can use either route to get this result

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