Offer an explanation for the following observations:
a. Hydrocarbon $\mathbf{1 0 - A}(\mathrm{p} K \approx 14)$ is considerably more acidic than $\mathbf{1 0}-\mathbf{B}(\mathrm{p} K \approx 22)$.
b. Hydrocarbon $\mathbf{1 0 - C}$ has an unusually small separation of its oxidation and reduction potentials, as established by electrochemical measurements. It is both easily reduced and easily oxidized. Both mono- and dications and monoand dianions can be readily formed.
c. The barrier for rotation about the marked bond in 10-D is only about 14 $\mathrm{kcal} / \mathrm{mol}$.
d. The hydrocarbon $\mathbf{1 0}-\mathbf{E}$ is easily reduced to a dianion. The ${ }^{1} \mathrm{HNMR}$ spectrum of the dianion shows an average downfield shift relative to the hydrocarbon. The central carbon shows a large upfield shift in the ${ }^{13} \mathrm{C}-\mathrm{NMR}$ spectrum.