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Problem 139 Easy Difficulty

Often the determination of the molar mass of a compound by osmotic pressure measurement is carried out at several different concentrations to get a more reliable average value. From the following data for the osmotic pressure of poly(methyl methacrylate) in toluene at $25^{\circ} \mathrm{C},$ determine graphically the molar mass of the polymer. [Hint: Rearrange Equation (12.8) so that $\pi$ is expressed in terms of $c,$ which is the number of grams of the solute per liter of solution.]

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Physical Properties of Solutions

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Video Transcript

So using the popularity of the solution, this can be determined by using the osmotic pressure equation that is given below. So we have C. Is equal to osmotic pressure over R. T. I. Well, we know that The automatic pressure 7.6 mm of Mercury. It's equal to not point, not want atmosphere Where T. is equal to 29 8.15 Calvin I. Is equal to one. We know that our gas constant, we solve for C. That is 4.08 times 10 to -4 malls polyta, where we can determine the amount of polymer which is equal to see, multiplied by the volume of solution. And what we sold for is 4.08 times 10 to the -4 moles. Where we can determine the molar mass of polymer, which is equal to the mass divided by the molecular weight, which is the mass divided by the moles. So what we get is 1.2 times 10 to the four g per mole. So the molar mass of our polymer here is 1.2 times 10 to the 4g per mole, Just to reiterate what we did to get. This final value was taken that five g of polymer divided by the moles that we calculated here.

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Raymond Chang, Kenneth A. Goldsby

Chemistry

Lizabeth Tumminello

Nadia Lara

Morgan Sizemore

Jacquelin Ho

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Chemistry

Lizabeth Tumminello

Nadia Lara

Morgan Sizemore

Jacquelin Ho

Raymond Chang, Kenneth A. GoldsbyChemistry

Lizabeth Tumminello

Nadia Lara

Morgan Sizemore

Jacquelin Ho

Raymond Chang, Kenneth A. Goldsby

Chemistry