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Often the determination of the molar mass of a compound by osmotic pressure measurement is carried out at several different concentrations to get a more reliable average value. From the following data for the osmotic pressure of poly(methyl methacrylate) in toluene at $25^{\circ} \mathrm{C},$ determine graphically the molar mass of the polymer. [Hint: Rearrange Equation (12.8) so that $\pi$ is expressed in terms of $c,$ which is the number of grams of the solute per liter of solution.]

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Chemistry 102

Chapter 12

Physical Properties of Solutions

Solutions

Rice University

University of Kentucky

Brown University

Lectures

03:58

In chemistry, a solution is a homogeneous mixture composed of two or more substances. The term "solution" is also used to refer to the resultant mixture. The solution is usually a fluid. The particles of a solute are dispersed or dissolved in the solvent. The resulting solution is also called the solvent. The solvent is the continuous phase.

05:06

In physics and thermodynamics, the natural tendency of a system to change its state is its tendency to increase the entropy of the system. It is a measure of the disorder in a system.

04:10

The osmotic pressure of so…

01:39

The molar mass of a polyme…

01:50

05:48

A solution containing $4.5…

01:28

06:24

A solution containing $5.5…

01:20

Analyzing Information The …

So using the popularity of the solution, this can be determined by using the osmotic pressure equation that is given below. So we have C. Is equal to osmotic pressure over R. T. I. Well, we know that The automatic pressure 7.6 mm of Mercury. It's equal to not point, not want atmosphere Where T. is equal to 29 8.15 Calvin I. Is equal to one. We know that our gas constant, we solve for C. That is 4.08 times 10 to -4 malls polyta, where we can determine the amount of polymer which is equal to see, multiplied by the volume of solution. And what we sold for is 4.08 times 10 to the -4 moles. Where we can determine the molar mass of polymer, which is equal to the mass divided by the molecular weight, which is the mass divided by the moles. So what we get is 1.2 times 10 to the four g per mole. So the molar mass of our polymer here is 1.2 times 10 to the 4g per mole, Just to reiterate what we did to get. This final value was taken that five g of polymer divided by the moles that we calculated here.

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