Question
Oil with kinematic viscosity $\nu=7.5 \times 10^{-4} \mathrm{ft}^{2} / \mathrm{s}$ flows at 45 gpm in a 100 -fi-long horizontal drawn-tubing pipe of 1 in. diameter. By what percentage ratio will the energy loss increase if the same flow rate is maintained while the pipe diameter is reduced to 0.75 in.?
Step 1
The velocity is given by the flow rate divided by the cross-sectional area of the pipe, which is $\frac{Q}{A} = \frac{Q}{\pi d^{2}/4}$. Substituting the given values, we get $v = 18.3 \, \text{ft/s}$. Show more…
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