Question
On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about $1.0 \times 10^{3} \mathrm{W} / \mathrm{m}^{2}$ . What is the electromagnetic energy contained in 5.5 $m^{3}$ of space just above the earth's surface?
Step 1
0 \times 10^{3} \mathrm{W} / \mathrm{m}^{2}$. We know that the intensity of electromagnetic radiation is related to the energy density (u) through the relation $S = u \cdot c$, where c is the speed of light. Show more…
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