Question
On a hot day, the temperature of an $80,000$ -L swimming pool increases by $1.50^{\circ} \mathrm{C}$ . What is the net heat transfer during this heating? Ignore any complications, such as loss of water by evaporation.
Step 1
We know that 1 liter is equal to $10^{-3}$ cubic meters. Therefore, the volume of the swimming pool in cubic meters is $80,000 \times 10^{-3} = 80 \, m^3$. Show more…
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