00:01
So we have a scenario in which we have a population size of 125 of which they've taken a random sample of 40 and we know that the mean of those 40 is 7.28 minutes and the sample standard deviation is 5.32 minutes.
00:22
And i'm gonna double check on that number.
00:24
That seems pretty big, but it is what it is.
00:27
That is correct.
00:28
And in part a we want to find a 99% confidence interval for the mean.
00:37
And so because we have more than our we take five% 7.28 plus or minus.
00:55
And the z star value that we use for 99% confidence is that 2.576.
01:03
Next we need to multiply by that standard air multiplied by that correction factor and that finite population correction factor.
01:13
So we're going to have that 5.32 divided by the square root of n, which was 40 and then times the square root of the 125 minus the sample size over one less than the sample size.
01:30
Excuse me.
01:30
The population size.
01:32
So when we do that calculation we have 7.28 -2.576 times the 5.32 divided by the square root of 40.
01:43
And then we need to multiply that by that correction factor and we have the numerator will be 85 underneath the radical divided by 1 24.
01:54
And when we get that calculation, the lower limit comes out to be five 4, 8 6 minutes and up to and will change that subtraction sign to an addition sign and that addition sign yields 9.074 minutes.
02:16
So we are 99% confident that that means of the populations lies somewhere in there.
02:22
Now on part b we want to look at 90% confidence interval for the total number of minutes.
02:31
That total number of minutes of, of minutes.
02:34
And and so we're going to take that total number of minutes which is going to be that 125 times our sample mean and our sample mean was at 7.28.
02:49
And we can get what that total is 125 times...