00:01
Given in the equation is the switch s and the circuit consisting of the resistance r and the inductor with inductance l connected with the battery of emfe.
00:23
Once the switch s is closed as in the figure, the time required for the current to reach any obtainable value depends in the part on value of the resistance.
00:34
Suppose that the emfe of the ideal battery is equals to 12 volt and inductance of the ideal inductor l is equal to 18 millie henry, then in how much time we need for the current 2 ampere to reach for first if resistance r is 1 oom, b if resistance is 5 oom, c, c, if resistance is 6 o.
01:09
And for the d part why is there a huge jump between the time in these two parts and for what value of r is the time required is least and what is that least time? for first part, when r is equals to 1 ome, we will use the relation in function of time v by r 1 minus e to the power minus r t by l.
01:52
Here we have r equals to 1 on, v equals to 12 volts and l equals to 18 into 10 to power minus 3.
02:04
Henry, on putting these values, an i, we have to reach 2mper, is equal to 12 by 1, 1 minus e to the power minus t by 18 into 10 to the power minus 3.
02:21
Henry, on simplifying and taking natural logarithm 5 by 6 equals to e to the power minus t by 18 into 10 to the power minus 3...