Question
One beaker contains 156 g of water at $22^{\circ} \mathrm{C},$ and a second beaker contains $85.2 \mathrm{g}$ of water at $95^{\circ} \mathrm{C}$ The water in the two beakers is mixed. What is the final water temperature?
Step 1
The total mass of the water is the sum of the masses of water in both beakers. Total mass = 156 g + 85.2 g = 241.2 g Show more…
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