00:01
Hi, students, welcome to the solution of problem number two, where we have a charge q1 and charge q2 separated by a distance of r.
00:15
Now, what is the force between q1 and q2? according to coulomb's law, it will be the electric constant times q1 times q2 divided by r square.
00:30
Now, according to the question, here we have inserted a brass plate between these charges.
00:40
Now, a brass plate is a metal.
00:46
It is a conductor.
00:50
In that case, the electric field inside the brass plate will be zero.
00:57
Now, consider the thickness of this blast plate to be t.
01:02
In that case this area or this distance of t where the electric field is zero does not contribute to the force between q1 and q2 so the new force f dash let us call it f dash it will be electric constant times q1 q2 times r minus t the hall square why i have subtracted t from the distance between q1 and q2 because that distance where the electric field is zero does not contribute to the force between q1 and q2 why the electric field is zero because it's a metal it's a conductor now since the denominator has decreased denominator has decreased it's basic algebra that the total value will increase...