00:01
So in this question they ask one compound of mercury with molar mass of 519 contains 77 .26 mercury 9 .25 % carbon and 1 .17 % hydrogen calculate the empirical formula.
00:16
So first of all write the given data molar mass mass that is equal to 519 then percentage of hg that is equal to to 77 .26%, then percentage of carbon 9 .25, then percentage of hydrogen 1 .17, then calculate its empirical formula, then percentage of oxygen that is equal to 100 minus some of percentage of other element.
01:22
That is 77 .26 plus 9 .25 % plus 1 .17 % plus 12 .32 % and that is equal to, so that is equal to 12.
01:55
12 .32 % of oxygen.
02:04
Then we know the equation that is element, then percentage equal to gram, then number of moles, then simplest and then last whole number, whole number.
02:36
So element is mercury, next carbon, next hydrogen, next hydrogen and last, and last.
02:49
Oxygen.
02:52
Then percentage are this is 77 .26 carbon is 9 .25.
03:01
Hydrogen is 1 .17 and oxygen it is 12 .32.
03:15
So, yon is 77 .26 divided by 200 .59.
03:26
That is equal to 0 .3852...