One gram each of ice, water, and water vapor are in equilibrium together in a closed container. The pressure is 4.58 mm of Hg , the temperature is $0.01^{\circ} \mathrm{C}$. Sixty calories of heat are added to the system. The total volume is kept constant. Calculate to within $2 \%$ the masses of ice, water, and water vapor now present in the container. Justify your answers.
(Hint: For water at $0.01^{\circ} \mathrm{C}$, the latent heat of fusion is $80 \mathrm{cal} / \mathrm{g}$, the latent heat of vaporization is $596 \mathrm{cal} / \mathrm{g}$, and the latent heat of sublimation is $676 \mathrm{cal} / \mathrm{g}$. Also note that the volume of the vapor is much larger than the volume of the water or the volume of the ice.)