00:01
Hello, today we are going to solve problem number seven.
00:05
In a population with two alleles, capital b and lowercase b, the allele frequency of lowercase b is 0 .4.
00:14
Uppercase b is dominant to lowercase b.
00:17
What is the frequency of individuals with the dominant phenotype if the population is in hardy -weinberg equilibrium? so first we want to determine the frequency of the dominant allele of p.
00:31
So we can use the second hardy -weinberg equation, which is p plus q equals one.
00:39
In this case, p is our dominant uppercase b allele.
00:44
So if we say, sorry about that, if we say p plus q equals one, in this case we're going to sub uppercase b and lowercase b equals 1, equals 1.
01:09
So b plus 0 .4 equals 1, which means that uppercase b should be 0 .6.
01:20
1 minus 0 .4 is 0 .6.
01:24
So now we want to determine the frequency of individuals with the dominant phenotype.
01:30
Okay, so remember the dominant phenotype can be two things...