One method for determining the depth of a well is to drop a stone into it and then measure the time it takes until the splash is heard. If $d$ is the depth of the well (in feet) and $t_{1}$ the time (in seconds) it takes for the stone to fall, then $d=16 t_{1}^{2},$ so $t_{1}=\sqrt{d} / 4 .$ Now if $t_{2}$ is the time it takes for the sound to travel back up, then $d=1090 t_{2}$ because the speed of sound is $1090 \mathrm{ft} / \mathrm{s} . \mathrm{So}$ $t_{2}=d / 1090 .$ Thus the total time elapsed between dropping the stone and hearing the splash is
$$t_{1}+t_{2}=\frac{\sqrt{d}}{4}+\frac{d}{1090}$$
How deep is the well if this total time is 3 s? (See the following figure.)