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Problem 11 Medium Difficulty

One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction $ y $ of the population who have heard the rumor and the fraction who have not heard the rumor.
(a) Write a differential equation that is satisfied by $ y. $
(b) Solve the differential equation.
(c) A small town has 1000 inhabitants. At $ 8 AM, $ 80 people have heard a rumor. By noon half the town has heard it. At what time will $ 90% $ of the population have heard the rumor?


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Related Courses

Calculus 2 / BC

Calculus: Early Transcendentals

Chapter 9

Differential Equations

Section 4

Models for Population Growth

Related Topics

Differential Equations

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Lectures

Video Thumbnail

13:37

Differential Equations - Overview

A differential equation is a mathematical equation for an unknown function of one or several variables that relates the values of the function itself and its derivatives of various orders. An ordinary differential equation (ODE) is a differential equation containing one or more derivatives of a function and their rates of change with respect to the function itself; it can be used to model a wide variety of phenomena. Differential equations can be used to describe many phenomena in physics, including sound, heat, electrostatics, electrodynamics, fluid dynamics, elasticity, quantum mechanics, and general relativity.

Video Thumbnail

33:32

Differential Equations - Example 1

A differential equation is a mathematical equation for an unknown function of one or several variables that relates the values of the function itself and its derivatives of various orders. An ordinary differential equation (ODE) is a differential equation containing one or more derivatives of a function and their rates of change with respect to the function itself; it can be used to model a wide variety of phenomena. Differential equations can be used to describe many phenomena in physics, including sound, heat, electrostatics, electrodynamics, fluid dynamics, elasticity, quantum mechanics, and general relativity.

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Watch More Solved Questions in Chapter 9

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Problem 9
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Problem 12
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Problem 18
Problem 19
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Problem 25

Video Transcript

Hey, it's Claire. So when you right here. So we're gonna let the number of people who have heard the rumors A and those who haven't be so we have why is equal to a over a plus b So are finding the rate of the spread. So it's d y over a dp, and we're seeing that the fraction of the population who have not heard the rumor is gonna be be over a plus B. And we get this to be a plus B minus day over a plus B. This is equal to one minus a over a plus B when we make this be equal to why we get one minus Why? So we get this to equal to K terms. Why comes one minus? Why, when Kate iss proportionally constant for part B, we have our equation from that we got from party. So we're gonna make people to why? And it's equal to one. So the solution is why of tea is equal to one over one plus que e to the negative. Katie, where a is equal to one minus y subzero over. Why subzero? So this is equal to one over one plus one minus y subzero Over. Why subzero comes e to the negative ke t which is equal to y subzero allover by sub zero plus one minus Why subzero eats a negative. Katie for part c, we're gonna make t is equal to zero. Got a t m. So we have Y sub zero is equal to 80 over 1000 which is 0.8 And by noon, we know the half of the town has heard the rumor. So you get why a four is equal to 0.5. We're getting our equation from part B, and we're just plugging it in using 0.0 a when. Why of zero when we got 0.0 Kate all over 0.8 plus 0.92 times e to the negative. Katie, we have zero point frying as equal to 0.8 all over 0.0 K plus 0.92 eats and negative for K. So the end of getting K is equal to negative 2.442 over negative for, and we get 0.612 Oh, and then we have why of tea is equal to 0.0 a all over 0.0. A school of 0.92 eats the negative 0.612 tea, and then we end up getting a T value of about 7.6, which is around seven hours and 36 minutes. So 90% of the rumor Hospira about 3:36 p.m.

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Calculus 2 / BC Courses

Lectures

Video Thumbnail

13:37

Differential Equations - Overview

A differential equation is a mathematical equation for an unknown function of one or several variables that relates the values of the function itself and its derivatives of various orders. An ordinary differential equation (ODE) is a differential equation containing one or more derivatives of a function and their rates of change with respect to the function itself; it can be used to model a wide variety of phenomena. Differential equations can be used to describe many phenomena in physics, including sound, heat, electrostatics, electrodynamics, fluid dynamics, elasticity, quantum mechanics, and general relativity.

Video Thumbnail

33:32

Differential Equations - Example 1

A differential equation is a mathematical equation for an unknown function of one or several variables that relates the values of the function itself and its derivatives of various orders. An ordinary differential equation (ODE) is a differential equation containing one or more derivatives of a function and their rates of change with respect to the function itself; it can be used to model a wide variety of phenomena. Differential equations can be used to describe many phenomena in physics, including sound, heat, electrostatics, electrodynamics, fluid dynamics, elasticity, quantum mechanics, and general relativity.

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