00:04
For part a, what is the delta s for the one -step isothermal compression? delta s is equal to q over t, and the heat is absorbed.
00:29
So delta s for the expansion is equal to 855 joules over 298 kelvin's, and this is equal to, 2 .87 joules per kelvin.
00:52
Delta a .s for the compression is equal to minus delta s for the expansion which is equal to minus 2 .87 joules per kelvin.
01:12
So the entropy change for the one -step is isotomal compression is minus 2 .87 joules per kelvin.
01:22
For part b, what is the delta s universe for the overall process, both expansion and compression.
01:36
So delta s universe is equal to delta s for the system plus delta s for the surroundings.
01:57
So the change in entropy of the system will be zero because entropy is a state function and the system was brought back to its original state.
02:09
So delta s of the system is zero.
02:14
Delta s for the surroundings is equal to minus q over t, which is equal to minus 855 joules over the temperature, which is 298 kelvin, which is equal to minus 2 .87 joules for kelvin...