00:01
So for part a, the energy transferred to the gas by heat, q, would be equalling mc delta t.
00:07
So this would be 1 .00 mole multiplied by 20 .79 joules per mole per kelvin, multiplied by 120 kelvin.
00:24
And this is giving us 2 .49 times 10 to the third joules.
00:33
So this would be your answer for part a.
00:36
And this would be again, the heat, the energy transferred to the gas by heat.
00:42
And so for part b, we're going to treat the neon as a monotomic ideal gas, which it is.
00:50
And we can say that the change in the internal energy would be three halves multiplied by the number of moles times the ideal gas constant, times the change in the temperature.
01:01
And again, this is specifically for a monotomic ideal gas...