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One of the roots is given. Find the other root. …

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48

Problem 19 Easy Difficulty

One of the roots is given. Find the other root.
$x^{2}-8 x+c=0 ;-3$

Answer

11

Related Courses

Algebra

Algebra 2 and Trigonometry

Chapter 5

QUADRATIC FUNCTIONS AND COMPLEX NUMBERS

Section 7

Sum and Product of the Roots of a Quadratic Equation

Related Topics

Equations and Inequalities

Quadratic Functions

Complex Numbers

Polynomials

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Watch More Solved Questions in Chapter 5

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48

Video Transcript

we have this equation. We know that one route is equal to negative three. We also know that if we take a route plus the other route that's gonna equals negative B over a. So it's just plug in what we know. One route is equal. Negative. Three. We don't know another roots. Let's just call it rude to And we do know Herbie Value is negative. Eight. So a negative negative eight is like a positive. We know our values. One in 8/1. Let's just rewrite that as eight. And there we go. So negative three plus what equals eight. Well, we can do a little bit of algebra and maybe you guys can already see it. If I add three. This goes away. If I add three, then we get our final answer of that other route is equal to 11

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