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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48

Problem 18 Easy Difficulty

One of the roots is given. Find the other root.
$x^{2}+15 x+c=0 ;-5$

Answer

$-10$

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Algebra

Algebra 2 and Trigonometry

Chapter 5

QUADRATIC FUNCTIONS AND COMPLEX NUMBERS

Section 7

Sum and Product of the Roots of a Quadratic Equation

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Watch More Solved Questions in Chapter 5

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Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
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Problem 31
Problem 32
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Problem 35
Problem 36
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Problem 38
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Video Transcript

he said the quadratic that we were given was X squared plus 15 x, uh, plus C. And we're told that one of the routes is my spy were asked to find the other route eso using the information that we were given. We know that 15 is the some off both of our roots, so we can put this as 15 equals minus five. And I'll just put the second room as, um are too eso also we have to do to find the other room is just south for our two. So to do that, we have our two equals 20 and that fine on that is the other route. So we have a roots is minus five and 20. So also you would have to do to find sea is just, um, multiply both routes since he represents the body. Uh oh. The route so minus five times 20 is minus 100. So we not only have our second route as 20 but we also have the value of C as my ass. 100

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