00:01
Hi, here in the first part of the given problem, diameter of a space station that is given as 890 meter, so its radius that will be r is equal to 445 meter, means half of its diameter.
00:41
Acceleration there should be means centipital acceleration it should be equal to acceleration due to gravity means 9 .8 meter per second is square so using an expression for the centripetal acceleration a c is equal to v square by r for v that is r omega so so square of r omega divided by r means it may also be written as r into omega square.
01:19
And for omega this is 2 pi f.
01:24
So it is expanded, bracket is open, bracket is expanded to get 4 pi square f square into r.
01:34
So frequency will be given by frequency of the rotation of this space station that will be given by 1 by 2 pi multiplied by square root of a by r.
01:46
Plugging in all the known values here, this is 1 by 2 times of 3 .14, multiplied by a, which should be 9 .8, divided by r, which is 445...