One procedure for the preparation of $\mathrm{Ir}_{4}(\mathrm{CO})_{12}$ is to start with commercially available $\mathrm{Na}_{2}\left[\operatorname{IrCl}_{6}\right]$ in ethanol and reduce it to the $\left[\operatorname{IrCl}_{6}\right]^{3-}$ ion with $\mathrm{I}^{-}$. Gaseous $\mathrm{CO}$ is then passed into the solution, and together with the addition of solid $\mathrm{K}_{2} \mathrm{CO}_{3}$, leads to the product, a black solid. Give a retrospective rationale of this sequence.