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Question number 49 is asking if the sun had a density equal to that of the universe's critical density, what would its size be? the critical density of the universe is estimated to be at a value of 10 to the minus 26 kilograms per cubic meter.
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For the purposes of this problem, we're assuming that the solar mass hasn't changed.
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We're going to make it so that it's still at a value of 1 .99 times 10 to the 30 kilograms.
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The reason the mass is important here is because in order to find the density of an object, we divide its mass by its volume.
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And the volume of a sphere is equal to a four -thirds pi times the cube of its radius.
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And the radius is what we're trying to find in this problem.
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We can get there by solving to find the volume.
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So let's rearrange our equation for density and say that mass divided by density will be equal to volume.
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So the volume of the sun will now be equal to 1 .99 times 10 to the 30 kilograms divided by 10 to the minus 26 kilograms per cubic meter.
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In performing our calculation, we find that the sun's volume in this problem is now equal to 1 .99 times 10 to the 56 cubic meters.
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And we're going to set that equal to 4 thirds pi r cubed.
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We want to solve for r.
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So, we're going to solve for r.
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So let's move 4 thirds pi to the other side of the equation.
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That means that r cubed will be equal to 3 fourths times 1 .99 times 10 to the 56 cubic meters over pi...