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Hello.
00:02
This question speaks about a snowball fight and a specific strategy in the snowball fights is that you throw a first shot at a sharper angle.
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So your opponent get distracted by this.
00:19
So let's assume that your opponent is here and you are staying at the origin.
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So you throw the first one with angle and in this case it's 70.
00:32
So the angle here that it makes with the horizontal is 70.
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And meanwhile, through another one at a lower angle so that it hits him directly.
00:48
And of course, the one here with lower angle will arrive faster than this one.
00:55
In this specific problem, we have that the initial velocity in both cases is 25 meters per.
01:04
Second and in the first part we're asked to get the angle at which you need to throw the second ball in order to rain to reach the same location and i can't answer this while drawing here and the answer should be 20 degree because that's the complementary of 70 both will add up to 90 degrees angle the actual reason for this is not of interest of for this problem, but if we see the equation of range, you will see that it's v .i squared sine 2 theta divided by g.
01:48
The interesting factor here is the 2 the sign of 2 theta because you can note here that sine 2 theta will be the same value for any two complementary angles.
02:04
So in case of 70, sign 140 is equal to sign 2 theta in case of 20, which is 40.
02:17
So this is from trig mathematics, and that's why complementary angles will land at the same position...