Question
One swimmer in a relay race has a 0.50 s lead and is swimming at a constant speed of $4.00 \mathrm{m} / \mathrm{s}$. The swimmer has $50.0 \mathrm{m}$ to swim before reaching the end of the pool. A second swimmer moves in the same direction as the leader. What constant speed must the second swimmer have in order to catch up to the leader at the end of the pool?
Step 1
50 s lead time. The distance covered is given by the product of speed and time. So, the distance covered by the first swimmer is $0.50 \, s \times 4.00 \, m/s = 2.00 \, m$. Show more…
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